x^2-7x+10=(x-5)(x-)

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Solution for x^2-7x+10=(x-5)(x-) equation: 



x^2-7x+10=(x-5)(x-)

We move all terms to the left:

x^2-7x+10-((x-5)(x-))=0

We add all the numbers together, and all the variables

x^2-7x-((x-5)(+x))+10=0

We multiply parentheses ..

x^2-((+x^2-5x))-7x+10=0



We calculate terms in parentheses: -((+x^2-5x)), so:

(+x^2-5x)

We get rid of parentheses

x^2-5x

Back to the equation:

-(x^2-5x)



We add all the numbers together, and all the variables

x^2-7x-(x^2-5x)+10=0

We get rid of parentheses

x^2-x^2-7x+5x+10=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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